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6x^2-43.5=250
We move all terms to the left:
6x^2-43.5-(250)=0
We add all the numbers together, and all the variables
6x^2-293.5=0
a = 6; b = 0; c = -293.5;
Δ = b2-4ac
Δ = 02-4·6·(-293.5)
Δ = 7044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7044}=\sqrt{4*1761}=\sqrt{4}*\sqrt{1761}=2\sqrt{1761}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1761}}{2*6}=\frac{0-2\sqrt{1761}}{12} =-\frac{2\sqrt{1761}}{12} =-\frac{\sqrt{1761}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1761}}{2*6}=\frac{0+2\sqrt{1761}}{12} =\frac{2\sqrt{1761}}{12} =\frac{\sqrt{1761}}{6} $
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